On Mon, 15 Jun 2009 20:01:58 -0700 (PDT) deostroll <deostr...@gmail.com> wrote:
> I want to be able to parse it into python objects. Any ideas?
JSON objects behave like python dicts (key:val pairs), so why not just
use them?
Both simplejson and py2.6-json (which is quite similar to the former)
do just that, but if you like JS attribute-like key access model you
can use it by extending the builtin dict class:
import types, collections
class AttrDict(dict):
'''AttrDict - dict with JS-like key=attr access'''
def __init__(self, *argz, **kwz):
if len(argz) == 1 and not kwz and isinstance(argz[0], types.StringTypes):
super(AttrDict, self).__init__(open(argz[0]))
else:
super(AttrDict, self).__init__(*argz, **kwz)
for k,v in self.iteritems(): setattr(self, k, v) # re-construct all
values via factory
def __val_factory(self, val):
return AttrDict(val) if isinstance(val, collections.Mapping) else val
def __getattr__(self, k):
return super(AttrDict, self).__getitem__(k)
__getitem__ = __getattr__
def __setattr__(self, k, v):
return super(AttrDict, self).__setitem__(k, self.__val_factory(v))
__setitem__ = __setattr__
if __name__ == '__main__':
import json
data = AttrDict(json.loads('{"host": "docs.python.org",'
' "port": 80,'
' "references": [ "collections",'
' "json",'
' "types",'
' "data model" ],'
' "see_also": { "UserDict": "similar, although'
' less flexible dict implementation." } }'))
print data.references
# You can always use it as a regular dict
print 'port' in data
print data['see_also']
# Data model propagnates itself to any sub-mappings
data.see_also.new_item = dict(x=1, y=2)
print data.see_also.keys()
data.see_also.new_item['z'] = 3
print data.see_also.new_item.z
--
Mike Kazantsev // fraggod.net
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