On Jun 8, 11:33 am, Gary Herron <gher...@islandtraining.com> wrote:
> Kless wrote:
> > Is there any way of to get the class name to avoid to have that write
> > it?
>
> > ---------------
> > class Foo:
> > super(Foo, self)
> > ---------------
>
> > * Using Py 2.6.2
>
> The question does not make sense:
> "to have WHAT write WHAT",
> and the code is wrong:
> the call to super fails
> But even so, perhaps this will answer your question
>
> >>> class Foo:
> ... pass
> ...
>
> >>> print Foo.__name__
> Foo
>
> >>> c = Foo
> >>> print c.__name__
> Foo
>
> >>> ob = Foo()
> >>> print ob.__class__.__name__
> Foo
>
> Gary Herron
I think the OP wants to call super without having to explicitly name
the type. If you use the self.__class__ approach in that scenario, you
can enter into a recursion loop with further inheritance.
class T(object):
"""I'm a standard class"""
def f(self):
print "function"
class S(T):
"""I call super using self.__class__"""
def f(self):
super(self.__class__, self).f()
class J(S):
"""I don't know about S' odd call."""
j = J()
j.f() # <--- Bombs
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