In <023a8d04$0$20636$c3e8...@news.astraweb.com> Steven D'Aprano <st...@remove-this-cybersource.com.au> writes:
>On Sat, 06 Jun 2009 15:59:37 +0000, kj wrote: >> In <h0e0oi$1es...@adenine.netfront.net> "tsangpo" >> <tsangpo.newsgr...@gmail.com> writes: >> >>>I want to ensure that the url ends with a '/', now I have to do thisa >>>like below. >>>url = url + '' if url[-1] == '/' else '/' >> >>>Is there a better way? >> >> It's a pity that in python regexes are an "extra", as it were. Otherwise >> I'd propose: >> >> url = re.sub("/?$", "/", url) >Thank goodness regexs are an "extra" in Python, because it discourages >noobs from pulling out the 80 pound sledgehammer of the regex engine to >crack the peanut of a test-and-concatenate: I was just responding to the OP's subject line. Whatever else one may say about my proposal, it *is* shorter. But thanks for the tip with timeit. That looks like a good module to know. kynn -- http://mail.python.org/mailman/listinfo/python-list