On Thu, 04 Jun 2009 18:26:49 -0700, chad wrote:
> Let's say I have a list of 5 files. Now lets say that one of the files
> reads nude333.txt instead of nude3.txt. When this happens, the program
> generates an error and quits. What I want it to do is just skip over the
> bad file and continue on with the next one.
This should give you some hints.
import errno
for name in list_of_file_names:
try:
f = open(name, 'r')
except IOError, e:
if e.errno == errno.ENOENT: # or just use 2 if you're lazy
# no such file, skip
continue
# some other more serious error, re-raise the exception
raise
do_something_with(f)
[...]
> def scroll_some_porn(now):
> while 1:
> for some_titty_porn in my_porn_collection:
> now.write(" \n")
> bitch_please = generate(some_titty_porn)
> now.write(bitch_please)
> time.sleep(10)
> now.write(" \n")
Shouldn't you have some way of escaping from the infinite loop other than
typing Ctrl-C at the console? I imagine your hands will be busy.
--
Steven
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