I'm sorry, I'm not really following your logic. Can you supply the statement with the three parameters ?
so if I want to reverse it fully using s[len(s)-1:x:-1] what would x be or is it impossible to express it in this way ?
Contrary to what I said above x should be _strictly_ less than -len(s).
You stop when you reach in the list the given end index (and don't take the item there) or if you leave the index range.
But -1 as an index is the same as (len(s)-1).
Therefore going from len(s)-1 down to -1 is the same as going from len(s)-1 to len(s)-1 hence an empty list.
And -len(s) is the same as 0 (my mistake above) But -len(s)-1 is not in the list thus you won't discard any limit.
The example: In [1]: s='12345'
In [2]: s[len(s)-1:0:-1] Out[2]: '5432'
In [3]: s[len(s)-1:-1:-1] Out[3]: ''
In [4]: s[-1],s[len(s)-1]
Out[4]: ('5', '5')In [5]: s[len(s)-1:-len(s)-1:-1] Out[5]: '54321'
In [6]: s[len(s)-1:-len(s):-1] Out[6]: '5432' -- http://mail.python.org/mailman/listinfo/python-list
