Peter Otten wrote: >>>> rows = data.splitlines() >>>> rows.sort(key=lambda line: int(line.split()[5])) >>>> rows.sort(key=lambda line: int(line.split()[2])) >>>> print "\n".join(rows)
Of course you can also sort in a single step: >>> rows = data.splitlines() >>> def key(row): ... columns = row.split() ... return int(columns[2]), int(columns[5]) ... >>> rows.sort(key=key) >>> print "\n".join(rows) Peter -- http://mail.python.org/mailman/listinfo/python-list
