Because in this case serialc is an numpy array. Since loadtxt returns a numpy-array. Furthermore
locals()['serialc_bin' + str(i+1)] creates a dictionary key (that's what I use the term "variable-like") serialc_bin1, serialc_bin2, ... not serialc_bin[0] with indexes. Gökhan On Fri, May 22, 2009 at 9:43 AM, David Robinow <drobi...@gmail.com> wrote: > On Fri, May 22, 2009 at 10:27 AM, Gökhan SEVER <gokhanse...@gmail.com> > wrote: > ... > > serialc = np.loadtxt(sys.argv[1], skiprows=skiprows).T > > for i in range(20): > > locals()['serialc_bin' + str(i+1)] = serialc[i+4] > > > > I don't know easier way than using locals() to construct variable-like > > identities in my program. > > I don't either. I also don't know why you feel you need to construct > variable-like identities. > Why is: > serialc_bin1 > better than > serialc_bin[0] > or, for that matter, > serialc[4] > > ??? > -- > http://mail.python.org/mailman/listinfo/python-list >
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