walterbyrd wrote:
I know that
s = r'x\nx'
means 'x' followed by a literal '\' followed by an 'n' (the '\n' is
not a carriage return).
s = r'x\tx'
means 'x' followed by a literal '\' followed by an 't' (the '\t' is
not a tab).
But, boundries seem to work differently.
s = re.sub(r'\bxxx\b', 'yyy', s)
Is *not* going to look for a literal '\' followed by 'b'
So I am confused about when escapes work within raw strings, and when
do escapes not work within raw strings.
>
The re module receives the regular expression in the form of a string
and then interprets it in its own way.
If you give the re module '\b', that's a backspace character, which is
treated as a literal character, just like 'x'.
If you give it r'\b', that _does_ contain 2 characters, but the re
module interprets it as representing a word boundary, except in a
character set [...] where that would be meaningless, so there it's
interpreted as representing a backspace character.
--
http://mail.python.org/mailman/listinfo/python-list
