On Fri, 2009-05-15 at 09:57 -0700, Tobiah wrote: > On Tue, 12 May 2009 14:17:54 +0200, Jaime Fernandez del Rio wrote: > > > This one I think I know... Try with: > > > > for k in sorted(word_count) : > > print k,"=",word_count[k] > > > > You need to do the sorting before iterating over the keys... > > Isn't that what's happening here? I read this as the > 'sorted' function iterating over the keys in word_count, > then passing that sorted list to the 'for' loop, for a > second iteration over the sorted pairs. > > No? > > Tobiah
The code and the description you are responding to are by the same poster. The OP posted something quite different. @Ronn: The for statement, which is the line ending with ":" has all the control over what order elements get processed in. Compare the following cases: >>> for x in ['hat', 'socks', 'shirt', 'pants']: ... print sorted(x) aht ckoss hirst anpst In this case, each element of the list gets sorted. That is, the letters of each string are put in alphabetical order. But they are processed in the order they appeared in the list. If you want to process the elements of the list in alphabetical order, you have to sort the list itself: >>> for x in sorted(['hat', 'socks', 'shirt', 'pants']): ... print x hat pants shirt socks Cheers, Cliff -- http://mail.python.org/mailman/listinfo/python-list
