Hi:
I would like to delete everything from column 54 on for each line
beginning with "ATOM". In the example in the attachment (sorry for the
attachment; I found no way with Google mail to have plain text mail)
the new line would become:
ATOM 49 NH1 ARG 84 84.628 41.570 44.395
without any blank space to the right. . Everything else should remain
at its original column. I have been looking for ???? statement, unable
(my big fault ) to find a right one. I tried with slices % but it
becomes unnecessarily complex.
Thanks
francesco
# Sample line
# 1 2 3 4 5 6 7 8
# 012345678901234567890123456789012345678901234567890123456789012345678901234567890
# ATOM 49 NH1 ARG 84 84.628 41.570 44.395 0.00 0.00 N
data = open('rec.crg', 'r')
outp = open('rec.strip.crg', 'w')
for L in data:
if L[3] == 'M':
L = L[:55] ???????
outp.write(L)
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