Ron_Adam <[EMAIL PROTECTED]> writes: > Here's yet another way to do it, but it has some limitations as well. > > import pickle > def pickle_it(filename, obj, commands): > try: > f = open(filename, 'r') > obj = pickle.load(f) > f.close() > except IOError: > pass > for i in commands: > i[0](i[1]) > f = open(filename, 'w') > pickle.dump(obj, f) > f.close() > > file = 'filename' > L = [] > > opps = [ (L.append,'more data'), > (L.append,'even more data') ] > pickle_it(file, L, opps)
Um - it doesn't look like this will work. You pass L in as the "obj" paremeter, and then it gets changed to the results of a pickle.load. However, you call L.append in the for loop, so the data will be appended to L, not obj. You'll lose an list elements that were in the pickle. <mike -- Mike Meyer <[EMAIL PROTECTED]> http://www.mired.org/home/mwm/ Independent WWW/Perforce/FreeBSD/Unix consultant, email for more information. -- http://mail.python.org/mailman/listinfo/python-list
