namekuseijin wrote: > On May 4, 9:15 am, David Robinow <drobi...@gmail.com> wrote: > >> On Mon, May 4, 2009 at 2:33 AM, namekuseijin >> >> <namekuseijin.nos...@gmail.com> wrote: >> >>>>>> ls = [(1,2), (3,4), (5, None), (6,7), (8, None)] >>>>>> [(x,y) for (x,y) in ls if y] >>>>>> >>> [(1, 2), (3, 4), (6, 7)] >>> >> Nope. That filters out 0 as well as None. Not what the OP asked for. >> > > True. I'm still a C programmer at heart I guess. ah, the flexibility > of 0... ;) > -- > http://mail.python.org/mailman/listinfo/python-list > > This seems to work for any length tuples :
>>> a = [(1,2), (3,4, 'goes'), (5,None), (6,7, 8, 'as', None), (8, None), (9, 0)] >>> [tup for tup in a if not [e for e in tup if e == None]] [(1, 2), (3, 4, 'goes'), (9, 0)]
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