I want to concatenate two bits string together: say we have '1001' and
'111' which are represented in integer. I want to concatenate them to
'1001111' (also in integer form), my method is:
('1001' << 3) | 111
which is very time consuming.
You omit some key details -- namely how do you know that "1001"
is 4 bits and not "00001001" (8-bits)? If it's a string (as your
current code shows), you can determine the length. However, if
they are actually ints, your code should work fine & be O(1).
This can be abstracted if you need:
def combine_bits(int_a, int_b, bit_len_b):
return (int_a << bit_len_b) | int_b
a = 0x09
b = 0x07
print combine_bits(a, b, 3)
However, if you're using gargantuan ints (as discussed before),
it's a lot messier. You'd have to clarify the storage structure
(a byte string? a python long?)
-tkc
PS: You may want to CC the mailing list so that others get a
crack at answering your questions...I've been adding it back in,
but you've been replying just to me.
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