On Tue, 21 Apr 2009 07:53:29 +0000, Steven D'Aprano wrote:

> Third strategy: divide the cube into eight half-cubes. Label then A
> through H:

Sheesh. Obviously they're not *half* cubes if there are eight of them. 
What I meant was that their edges are half as long as the edge of the 
1x1x1 cube.

-- 
Steven
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