Scott David Daniels wrote:
Assuming you really are going for "is" comparison, how about: max(id(x) for x in mylist) == min(id(x) for x in mylist)It has the advantage that if [id(x) for x in mylist] = [2N, 1N, 3N], you get the answer you desire.
Oops -- got me! -John -- http://mail.python.org/mailman/listinfo/python-list
