On Apr 11, 11:18 pm, George Sakkis <george.sak...@gmail.com> wrote: > The numpy import *is* important if you want to use numpy-specific > features; there are many "tricks" you can do easily with numpy arrays > that you have to write manually for, say, regular python lists. For > example what you want to do is trivial with numpy: > > >>>import numpy as N > >>> s = N.array([ 0.84971586, 0.05786009, 0.9645675, 0.84971586, > >>> 0.05786009, > > 0.9645675, 0.84971586, 0.05786009, 0.9645675, 0.84971586, > 0.05786009, 0.9645675])>>> # convert to a 4by3 array in place > >>> s.shape = (4,3) > >>> s > > array([[ 0.84971586, 0.05786009, 0.9645675 ], > [ 0.84971586, 0.05786009, 0.9645675 ], > [ 0.84971586, 0.05786009, 0.9645675 ], > [ 0.84971586, 0.05786009, 0.9645675 ]])
Thanks very much - works fine! Now for a follow-up question:) Actually my original list called "mylist" contains 81217 elements - I shape those into >>> len(mylist) 81217 >>> s = N.array(mylist) >>> s.shape = (241,337) which works because the "total size of new array must be unchanged" (241x337=81217) Now this "matrix" actually is a 2D colorcoded map - I want to plot this using the imshow splot routine in mayavi2.. However, there might be a problem: I believe that sometimes my original array will not exactly contain 81217 elements, but maybe only 81216 or so. Nevertheless, I know that time x times y - structure will always be the same (that is, 241 columns). What is of interest to me is the first 241 x 241 part of the matrix anyway. Is there an easy way to reshape my original array into a symmetric 241x241 matrix? Thanks a lot again, Bernard -- http://mail.python.org/mailman/listinfo/python-list
