> print locals()['__file__'].split(sep)[-1] .split(sep)[-1] is pretty dense reading. try: print os.basename(locals()['__file__'])
runes wrote: > Is it a more pythonic way of finding the name of the running script > than these? > > from os import sep > from sys import argv > > print argv[0].split(sep)[-1] > # or > print locals()['__file__'].split(sep)[-1] > # or > print globals()['__file__'].split(sep)[-1] M.E.Farmer -- http://mail.python.org/mailman/listinfo/python-list
