> I'm not 100% sure what you're trying to do, but the above is horribly > non-portable. You probably want to be looking at socket.getpeername() and > socket.getsockname().
This only works if you are actually connected. I think he wants to find out the local address without actually connecting. > In general, concepts like "the address of an interface" are difficult. In > many OS's, a given interface may have multiple addresses. This is > especially true in IPv6 where you've have both link local and global > unicast addresses on the same interface. In Linux, you can only have one IPv4 address per interface (and you have to use alias interfaces, such as eth0:0, to assign multiple addresses to a physical link). For IPv6 and Linux, you are right. > > Can you back up a few steps and describe what it is that you're trying to > do, i.e. the use case? I guess he wants to do the equivalent of ifconfig. Regards, Martin -- http://mail.python.org/mailman/listinfo/python-list
