Quoting PK <superp...@gmail.com>:
> So I'm trying to see whats the cleanest way to do this:
>
> I have a
>
> checklist = [ax, bx, by, cy ..] (a combination of a,b,c with x and y,
> either both on one)
>
> allist = [a,b,c,....]
> xlist = [x, y, ..]
>
[...]
> now the problem is I want to include alpha in missing list only if
> none of the combinations from xlist with alpha are in checklist.
This is untested:
for alpha in alist:
for xy in xlist:
if alpha+xy in checklist:
break
else:
missing.append(alpha)
(note that the "else" is for the "for", not the "if")
You could also try the any/all functions from python2.5:
for alpha in alist:
if not any(alpha + xy in checklist for xy in xlist):
missing.append(alpha)
Or the really not recommended one-liner:
missing = [alpha for alpha in alist if not any(alpha + xy in checklist for xy in
xlist)]
(remember, all of this is untested)
--
Luis Zarrabeitia
Facultad de Matemática y Computación, UH
http://profesores.matcom.uh.cu/~kyrie
--
Participe en Universidad 2010, del 8 al 12 de febrero de 2010
La Habana, Cuba
http://www.universidad2010.cu
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