Uwe Mayer wrote:
> Hi,
>
> I've got a ISO 8601 formatted date-time string which I need to read into a
> datetime object.
> Is there a shorter way than using regular expressions? Is there a sscanf
> function as in C?
in addition to the other comments...
I like re, because it gives me the most control. See below.
import re
import datetime
class Converter:
def __init__( self ):
self.isoPattern = re.compile( "(\d\d\d\d)-(\d\d)-(\d\d)[tT
](\d\d):(\d\d):(\d\d)" )
def iso2date( self, isoDateString ):
match = self.isoPattern.match( isoDateString )
if not match: raise ValueError( "Not in ISO format: '%s'" %
isoDateString )
return datetime.datetime(
int(match.group(1)),
int(match.group(2)),
int(match.group(3)),
int(match.group(4)),
int(match.group(5)),
int(match.group(6))
)
c = Converter()
def demo( iso ):
try:
date = c.iso2date( iso )
print "Input '%s' -> datetime: %s" % ( iso, date )
except ValueError, e:
print str(e)
demo( "2005-04-21T12:34:56" )
demo( "2005-04-21 12:34:57" )
demo( "2005-04-2 12:34:57" )
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