On Sun, Apr 5, 2009 at 8:17 AM, Good Z <goodz...@yahoo.com> wrote:
> Dear all,
> I am using Python 2.4.3 for my project. We need to use HTTPS with
> python2.4.3 unfortunately it seems httplib is not working fine for me. Below
> is small code that works well with Python2.6.1 but not with Python2.4.3.
> Unfortunately its not possible for me to move away from Python 2.4.3. Would
> request if anyone has any idea how to make this programs work in
> Python2.4.3.
>
> import httplib
> conn1 = httplib.HTTPSConnection(WEBSITE_ADDRESS)
> conn1.putrequest('GET', RELATIVE_ADDR)
> conn1.putheader('Connection', 'close')
> conn1.endheaders()
>
> r1 = conn1.getresponse()
>
> data1 = r1.read()
> print data1
> conn1.close()
>
> One executing the above program, it crash while reading the response and
> gives following error:
> Traceback (most recent call last):
> File "<pyshell#11>", line 1, in <module>
> r1 = conn1.getresponse()
> File "C:\Python25\lib\httplib.py", line 928, in getresponse
> response.begin()
> File "C:\Python25\lib\httplib.py", line 385, in begin
> version, status, reason = self._read_status()
> File "C:\Python25\lib\httplib.py", line 349, in _read_status
> raise BadStatusLine(line)
> BadStatusLine
>
> Any help would be appreciated.
>
> Best Regards,
> Mike.
>
>
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> http://mail.python.org/mailman/listinfo/python-list
>
>
You may be running into http://bugs.python.org/issue5007 - if you could
post the url of the site you're trying to open, I can test to see if it
works in 2.5/2.6 (It won't if you're running into that bug).
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