Hi
Is there any way to get the name of the file opened from the file object
'f' which i get through the code
f = os.fdopen(os.open("trial', os.O_WRONLY|os.O_CREAT), "w")
The situation will be like i can access only the above variable 'f'.
f.name is having '<fdopen>' instead of filename 'trial'
Or if not possible can anyone suggest a solution where my requirements
are
a) i need file access through os module
b) i need file object and not file descriptor as its more easy to use
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Thanks & Regards
visco
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