En Thu, 26 Mar 2009 11:42:57 -0300, Philipp Lies
<philipp.l...@googlemail.com> escribió:
I'm trying to run the python profiler on some code but I always get
NameErrors, even for the simplest case taken from the docs:
import profile
def foo():
a = 5
def prof():
profile.run('foo()')
When I run prof() I get the following output:
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "dummy.py", line 11, in prof
profile.run('foo()')
File "/usr/lib/python2.5/profile.py", line 70, in run
prof = prof.run(statement)
File "/usr/lib/python2.5/profile.py", line 456, in run
return self.runctx(cmd, dict, dict)
File "/usr/lib/python2.5/profile.py", line 462, in runctx
exec cmd in globals, locals
File "<string>", line 1, in <module>
NameError: name 'foo' is not defined
The very same error I get using cProfile.
It works when I call
profile.runctx('foo()', globals(), locals())
which should be the same as run('foo()'), shouldn't it?
Not exactly -- profile.run doesn't "extract" globals and locals from the
calling frame, as you appear to assume. It simply uses the namespace from
the __main__ module:
(profile.c, class Profile):
def run(self, cmd):
import __main__
dict = __main__.__dict__
return self.runctx(cmd, dict, dict)
This works when the called function is actually in the __main__ module.
From your traceback, you're first *importing* dummy.py and then *calling*
prof(). Call prof() directly inside dummy.py and it should work. That is,
add this line at the end:
prof()
and invoke it using: python dummpy.py
--
Gabriel Genellina
--
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