On Mar 27, 7:48 pm, mark.sea...@gmail.com wrote: > On Mar 27, 4:00 pm, Miles <semantic...@gmail.com> wrote: > > > > > > > On Fri, Mar 27, 2009 at 6:56 PM, Gabriel Genellina wrote: > > > En Fri, 27 Mar 2009 18:43:16 -0300, <mark.sea...@gmail.com> escribió: > > >> Python print recognizes the local constant "dog", but it goes and > > >> fetches the __int__ type from my object-based class, even though it's > > >> value is a long. Then Python print doesn't expect a long to come back > > >> and bombs out. I don't want to force the main program to cast the > > >> long value getting returned. I know Python print can print a long, > > >> but how can I make it select the __long__ instead of the __int__ ? > > > > This bug was corrected in version 2.6 - see > > >http://bugs.python.org/issue1742669 > > > If you have to stay with 2.5 I'm afraid any solution would require to > > > modify > > > your code: > > > > -- put long() around those arguments > > > -- "%s" % format_hex(val) (where format_hex does the long conversion) > > > -- redefine __str__ and use %s > > > Or make your class a subclass of long. > > > -Miles- Hide quoted text - > > > - Show quoted text - > > Absolute genius. Wish I had thought of that. Thanks to both of you.- Hide > quoted text - > > - Show quoted text -
I mean all three of you. :) -- http://mail.python.org/mailman/listinfo/python-list
