TP wrote:
Hi everybody,This example gives strange results: ######## def foo( l = [] ): l2 = l print l2 for i in range(10): if i%2 == 0: l2.append( i ) yield i ########[i for i in ut.foo()][] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9][i for i in ut.foo()][0, 2, 4, 6, 8] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9][i for i in ut.foo()][0, 2, 4, 6, 8, 0, 2, 4, 6, 8] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] ... How to explain this behavior? Why l is not [] when we enter again the function foo()?
Read http://www.ferg.org/projects/python_gotchas.html#contents_item_6 -- http://mail.python.org/mailman/listinfo/python-list
