John Posner <jjpos...@snet.net> wrote: > > [snip] > > > If you want next(g) to yield 3, you'd have to do something like: > > > > > > g = (x for x in s[:]) > > > > > > where s[:] makes a copy of s that is then iterated over. > > > BTW, this simpler statement works, too: > > g = iter(s[:])
Yes, but one presumes that in the real code that prompted the OP's question he wasn't just returning 'x'. -- R. David Murray http://www.bitdance.com -- http://mail.python.org/mailman/listinfo/python-list
