Luis Zarrabeitia wrote:
On Tuesday 17 March 2009 06:04:36 pm Jim Garrison wrote:
with open(filename, "rb") as f:
    for buf in iter(lambda: f.read(1000),''):
        do_something(buff)

This is the most pythonic solution yet.

Thanks to all the responders who took time to ponder this seemingly
trivial question.  I learned a lot about the Python mind-set.
--
http://mail.python.org/mailman/listinfo/python-list

Reply via email to