mattia: > Now, some ideas (apart from the double loop to aggregate each element of > l1 with each element of l2):
>>> from itertools import product >>> list(product([1,2,3], [4,5])) [(1, 4), (1, 5), (2, 4), (2, 5), (3, 4), (3, 5)] Bye, bearophile -- http://mail.python.org/mailman/listinfo/python-list