what is I just set "colors": self.opt['arg_opts_options']['imp_colors']
then they are both pointing to the same place, correct? -Alex Goretoy http://www.goretoy.com On Sun, Mar 15, 2009 at 11:16 PM, alex goretoy <aleksandr.gore...@gmail.com>wrote: > i did this because this will read colors into a nested variable > > How would i make this work the way you suggest? I already have it working > now :) > > Not able to set to dict value with setattr, how to do this too(sorry if off > subject)? > > I can set it like this: > > for i in self.opt['properties'].keys(): > self.opt[i] = > getattr(self.opt['properties_object'], i) > but not like this: > for i in self.opt['properties'].keys(): > setattr(self, opt[i], > getattr(self.opt['properties_object'], i)) > -Alex Goretoy > http://www.goretoy.com > > > > On Sun, Mar 15, 2009 at 6:41 PM, MRAB <goo...@mrabarnett.plus.com> wrote: > >> alex goretoy wrote: >> >>> ok now for the final result, i decided to split options out to a separate >>> dict of lists, does this look right to every one, I currently have error >>> somewhere else in my code so can't test this right now, Is this a good >>> method to do this? or is there another option? >>> >>> [snip] >> First of all, *don't use "is" and "is not" to test for equality*; use "==" >> and "!=". >> >> When you split the options out like that you get duplication. >> >> You have, for example: >> >> ... >> "colors": ["c", "cl", "col", ...] >> ... >> >> and: >> >> ... >> "imp_colors": ["c", "cl", "col", ...] >> ... >> >> Couldn't you put them into one dict, something like: >> >> ... >> "colors": ("imp_colors", ["c", "cl", "col", ...]) >> ... >> >> >> -- >> http://mail.python.org/mailman/listinfo/python-list >> > >
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