Maxim Khitrov wrote:
Perhaps a different example would help explain what I'm trying to do:
class Case1(object):
def __init__(self):
self.count = 0
self.list = []
def inc(self):
self.count += 1
self.list.append(self.count)
def val(self):
return (self.count, self.list)
OK, so .count and .list (BAD IDEA TO USE BUILT-IN NAME) are not
constants, as you previously implied.
class Case2(object):
count = 0
list = []
def inc(self):
self.count += 1
self.list.append(self.count)
def val(self):
return (self.count, self.list)
for i in xrange(10):
You really only need one value of i for a test. But you need multiple
instances of each class
c1 = Case1()
c2 = Case2()
c1a, c1b = Case1(), Case1()
c2a, c2b = Case2(), Case2()
for j in xrange(i):
c1.inc()
c2.inc()
c1a.inc(), c1b.inc()
c2a.inc(), c2b,inc()
v1, l1 = c1.val()
v2, l2 = c2.val()
print(c1a.val(), c1b.val(), c2a.val(), c2b.val())
print v1 == v2, l1 == l2
# just look as all four tuples
The only difference between Case1 and Case2 classes is where the count
and list attributes are defined.
and that 'only difference makes a major difference. Make two instances
of each class and you will see how.
Terry Jan Reedy
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