mattia wrote:
> Il Sat, 14 Mar 2009 10:35:59 +0100, Peter Otten ha scritto:
>
>> mattia wrote:
>>
>>> How can I convert the following string:
>>>
>>> 'AAR','ABZ','AGA','AHO','ALC','LEI','AOC',
>>> EGC','SXF','BZR','BIQ','BLL','BHX','BLQ'
>>>
>>> into this sequence:
>>>
>>> ['AAR','ABZ','AGA','AHO','ALC','LEI','AOC',
>>> EGC','SXF','BZR','BIQ','BLL','BHX','BLQ']
>>
>>>>> s = "'AAR','ABZ','AGA','AHO','ALC','LEI','AOC'"
>>>>> csv.reader(StringIO.StringIO(s), quotechar="'").next()
>> ['AAR', 'ABZ', 'AGA', 'AHO', 'ALC', 'LEI', 'AOC']
>>
>> or
>>
>>>>> s = "'AAR','ABZ','AGA','AHO','ALC','LEI','AOC'" list(compile(s,
>>>>> "nofile", "eval").co_consts[-1])
>> ['AAR', 'ABZ', 'AGA', 'AHO', 'ALC', 'LEI', 'AOC']
>>
>> Peter
>
> Ok, and what about if the string is "['AAR', 'ABZ', 'AGA', 'AHO', 'ALC']"
> I wanted to use eval(string) but it is discouraged, they say.
If you use the csv module you can remove the [] manually
assert s.startswith("[")
assert s.endswith("]")
s = s[1:-1]
compile() will work without the enclosing list(...) call.
Yet another one is
flights = re.compile("'([A-Z]+)'").findall(s)
if any(len(f) != 3 for f in flights):
raise ValueError
Peter
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