Fab86 <fabien.h...@gmail.com> writes:
> On Mar 5, 5:23 pm, Marco Mariani <ma...@sferacarta.com> wrote:
>> Fab86 wrote:
>> > Is it possible to get the program to catch the exception, wait 10
>> > seconds, then carry of from where it was rather than starting again?
>>
>> something like this? probably works in PASCAL as well :)
>>
>> > i=0
>> > while i < len(stuff):
>> > try:
>> > do_with(stuff[i])
>> > except SomeError:
>> > sleep(10)
>> > continue
>> > i+=1
>>
>>
>
> using sleep and then continue just makes the search start from the
> first search term like before.. Would it be easier to understand if I
> posted sections of my code?
>
> i = 0
> k = open('blah', 'w')
> domains = ["au", "ca", "nl", "be", "...]
> srch = WebSearch(app_id=YahooKey)
>
> while i<200:
> try:
> for domain in domains:
> srch.query = "test site:.%s" % domain
> res = srch.parse_results()
> print >> k, res.total_results_available
> i = i + 1
>
> except SearchError:
>
> (I currently close then reopen document here then restart i to 0)
>
> Any ideas?
You should check out the sched module for scheduling tasks.
<code>
import sched, time
domains = ["au", "ca", "nl", "be", "ru", "us", "de"]
s = sched.scheduler(time.time, time.time)
def do_query(query, domain):
search.query = "%s site:.%s" % (query, domain)
try:
result = search.parse_results()
except SearchError, e:
print >> sys.stderr, e
else:
print >> k, result
for domain in domains:
s.enter(2, 1, do_query, domain)
s.run()
</code>
YMMV
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