Hi There,
I am trying to connect to a web service but I am getting HTTP 400, I
am not too concerned about the HTTP error - but what I'd like to know
if there is anyway I can read the response body in the HTTP 400 or 500
case? Does the HTTPError allow this? or the urllib2 in anyway?
This is what I have at the moment...
import sys, urllib2
import socket
class APIConnector:
def connect(*args):
length = len(args[2])
headers = {"Content-Length": length, "Content-Type":
"text/xml", "SOAPAction": "\"http://some.api.com/RemovedAction\""}
try:
#url, body, headers
rq = urllib2.Request(args[1], args[3],
headers)
rs = urllib2.urlopen(rq)
print rs.read()
except urllib2.HTTPError, e:
conn = e
print 'error', conn.code, 'message: ',
conn.msg, 'filename: ', conn.filename, 'headers: ', conn.hdrs, 'body:
', conn.read()
I thought that conn.read() may show the body, but it seems not... Can
anyone help please, or suggest another way around? I am using python
2.5 installed with MAC OS X Leopard.
Cheers
Stu
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