En Thu, 26 Feb 2009 11:00:30 -0200, Boris Borcic <bbor...@gmail.com>
escribió:
Chris Rebert wrote:
On Thu, Feb 26, 2009 at 3:05 AM, Clarendon <jine...@hotmail.com> wrote:
...
L=['a', 'b', 'c', 'a']
I want to delete all 'a's from the list.
But if L.remove('a') only deletes the first 'a'.
How do you delete all 'a's?
There are several ways. I'd go with a list comprehension:
and for a couple other ways
while 'a' in L : L.remove('a')
This is probably the worst way, takes cuadratic time (and two searches per
loop).
L = filter('a'.__ne__,L)
And this is probably the fastest. But not all types define __ne__ so a
more generic answer would be:
from functools import partial
from operator import ne
L = filter(partial(ne, 'a'), L)
Of course, this is only relevant if L is large and there are many
duplicates. In other cases I'd stick with the list comprehension as posted
by Chris Rebert.
--
Gabriel Genellina
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