TechieInsights wrote:
> On Feb 12, 9:03 am, Catherine Heathcote
> <catherine.heathc...@gmail.com> wrote:
>> But I just cant find it. How do I do an or, as in c/c++'s ||? Just
>> trying to do something simple, the python equivilent of:
>>
>> if(i % 3 == 0 || i % 5 == 0)
>>
>> Thanks.
>
> in 2.5 and above you can do
> if any(i%3 == 0, i%5 == 0)
[nitpick: you need an additional set of brackets inside the call to any]
I love it! A totally unnecessary creation of a tuple and a function call
instead of a straight-forward 'or' expression. Can we make this simple task
even more obfuscated?
not all( (i%3 != 0, i%5 !=0) )
Still not convoluted enough.
all( (sum(int(c) for c in str(i))%3 in (1, 2),
str(i).endswith(chr(53)) - 1,
str(i).endswith(chr(48)) - 1) ) - 1
Hmmm... how can I get rid of that pesky %3?
all( (divmod( sum(int(c) for c in str(i)),
41^42)[1] in (1, 2),
str(i).endswith(chr(53)) - 1,
str(i).endswith(chr(48)) - 1) ) - 1
Okay, that makes my brain hurt. I think it will do.
:-)
--
Steven
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