On Mon, Feb 9, 2009 at 4:18 PM, Lionel <lionel.ke...@gmail.com> wrote: > On Feb 9, 4:04 pm, Jean-Paul Calderone <exar...@divmod.com> wrote: >> On Mon, 9 Feb 2009 15:20:05 -0800 (PST), Lionel <lionel.ke...@gmail.com> >> wrote: >> >Hello. I've been scouring the web looking for something to clear up a >> >little confusion about the use of "super()" but haven't found anything >> >that really helps. Here's my simple example: >> >> > [snip] >> >> >"super(Child,self).__init__(filePath) >> >TypeError: super() argument 1 must be type, not classobj" >> >> >What have I done wrong? Thanks in advance for any help. >> >> Consider whether you really need to use super(). >> >> http://fuhm.net/super-harmful/ >> >> Jean-Paul > > Yes, I came across that essay...and it scared me. Will my base class > initializer always get called regardless of whether or not I use super > ()?
No, it is not called unless you /explicitly/ call it (either using super() or manually via BaseClassName.__init__(self, other, args, here)) in your subclass' __init__ or you don't define an __init__ for your subclass (and it inherits __init__ from its first superclass). Cheers, Chris -- Follow the path of the Iguana... http://rebertia.com -- http://mail.python.org/mailman/listinfo/python-list
