On 2009-02-09 17:20, Lionel wrote:
Hello. I've been scouring the web looking for something to clear up a
little confusion about the use of "super()" but haven't found anything
that really helps. Here's my simple example:
class Parent:
def __init__(self, filePath):
.
.
Do some processing with "filePath"
.
.
class Child(Parent):
def __init__(self, filePath):
super(Child,self).__init__(filePath)
.
.
Do some additional Child-specific processing on filePath
.
.
As I understand it, "super()" will invoke the initializer of the base
class. There must be something wrong with the above syntax since I'm
getting:
"super(Child,self).__init__(filePath)
TypeError: super() argument 1 must be type, not classobj"
What have I done wrong? Thanks in advance for any help.
super() only works on the "new-style" classes introduced in Python 2.2. You need
to make Parent subclass from object:
class Parent(object):
...
--
Robert Kern
"I have come to believe that the whole world is an enigma, a harmless enigma
that is made terrible by our own mad attempt to interpret it as though it had
an underlying truth."
-- Umberto Eco
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