Christopher Culver wrote:
Tino Wildenhain <t...@wildenhain.de> writes:
so instead you would use archive = zipfile.ZipFile(remotedata)
That produces the following error if I try that in the Python
interpreter (URL edited for privacy): ....
remotedata = urllib2.urlopen("http://...file.zip";)
archive = zipfile.ZipFile(remotedata)
No, he means you need to pull down the remote data. Zip file reading
is not done in a single pass; it needs to seek to find the directory,
then again to get to the data for any particular file. Seeking around
a file does not work so well across the net.
Try something like:
>>> import zipfile
>>> import urllib2
>>> import StringIO # or cStringIO as StringIO
>>> remotehandle = urllib2.urlopen("http://...file.zip";)
>>> zipdata = StringIO.StringIO(remotehandle.read())
>>> remotehandle.close()
>>> archive = zipfile.ZipFile(zipdata)
or:
>>> with urllib2.urlopen("http://...file.zip";) as remotehandle:
... zipdata = StringIO.StringIO(remotehandle.read())
... archive = zipfile.ZipFile(zipdata)
--Scott David Daniels
scott.dani...@acm.org
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