Lionel wrote:
On Feb 2, 1:07 pm, "Diez B. Roggisch" <de...@nospam.web.de> wrote:
This is written very slowly, so you can read it better:
Please post without sarcasm.
This is the output from my Python shell:
DatafilePath = "C:\\C8Example1.slc"
ResourcefilePath = DatafilePath + ".rsc"
DatafileFH = open(DatafilePath)
ResourceFh = open(ResourcefilePath)
DatafilePath
'C:\\C8Example1.slc'
ResourcefilePath
'C:\\C8Example1.slc.rsc'
Here the extension is '.rsc' ...
It seems to run without trouble. However, here is the offending code
in my class (followed by console output):
class C8DataType:
def __init__(self, DataFilepath):
try:
DataFH = open(DataFilepath, "rb")
except IOError, message:
# Error opening file.
print(message)
return None
ResourceFilepath = DataFilepath + ".src"
... but here the extension is '.src'.
Is that the problem.
print(DataFilepath)
print(ResourceFilepath)
# Try to open resource file, catch exception:
try:
ResourceFH = open(ResourceFilepath)
except IOError, message:
# Error opening file.
print(message)
print("Error opening " + ResourceFilepath)
DataFH.close()
return None
Console output when invoking as "someObject = C8DataType("C:\
\C8Example1.slc")" :
C:\C8Example1.slc
C:\C8Example1.slc.src
[Errno 2] No such file or directory: 'C:\\C8Example1.slc.src'
Error opening C:\C8Example1.slc.src
[snip]
It can't find "C:\C8Example1.slc.src", but I think you intended
"C:\C8Example1.slc.rsc".
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