Hi Folks, Python newbie here. I'm trying to open (for reading) a text file with the following filenaming convension:
"MyTextFile.slc.rsc" My code is as follows: Filepath = "C:\\MyTextFile.slc.rsc" FileH = open(Filepath) The above throws an IOError exception. On a hunch I changed the filename (only the filename) and tried again: Filepath = "C:\\MyTextFile.txt" FileH = open(Filepath) The above works well. I am able to open the file and read it's contents. I assume to read a file in text file "mode" the parameter is scanned for a ".txt" extension, otherwise the Python runtime doesn't know what version of "open(...)" to invoke. How do I pass the original filename (MyTextFile.slc.rsc) and get Python to open it as a text file? Thanks in advance everyone! -- http://mail.python.org/mailman/listinfo/python-list
