En Sun, 01 Feb 2009 07:27:26 -0200, asit <lipu...@gmail.com> escribió:
My program contains some sys.exit(1) and when its executed an
exception known as SystemExit is thrown.
This is normal behaviour - but you should not "see" the SystemExit. Do you
mean that a stack trace appears in the console?
I tried to handle bu using following code snippet
if __name__ == "__main__":
try:
main() #main contains sys.exit(1)
except KeyboardInterrupt:
print "aborted by user"
except SystemExit:
pass
But it does not work.
I've tested adding this:
def main():
sys.exit(1)
and it exited normally, even after removing the SystemExit clause.
Can anyone help me out ???
Though KeyboradInterrupt is handled, but why SystemExit is not
handles ????
Perhaps there is another try/except somewhere else that handles SystemExit?
Look for bare except clauses, like
try:
except: ...
They should *not* be used. With Python 2.5 and above, theh "catch-all"
should be written as:
try:
except Exception: ...
If you are using 2.4 or earlier, should be:
try:
except (SystemExit, KeyboardInterrupt): raise
except: ...
--
Gabriel Genellina
--
http://mail.python.org/mailman/listinfo/python-list
