On Jan 22, 6:45 pm, cburns <cburns4...@gmail.com> wrote: > In the code below, bar() seems to work, foo() seems broken. > > % python -V > Python 2.6.1 > > % cat exec1.py > > def foo(i) : > exec "i = i + 1" in locals(), globals() > print "i=%d" % i > > def bar(j) : > exec "j = j + 1" > print "j=%d" % j > > foo(0) > bar(0) > > % python exec1.py > i=0 > j=1 > > What I really wanted to do was something like: > > exec text in globals(), inspect.currentframe(1).f_locals but > that didn't work either.
Trying to modify locals() in a function is undefined behavior. > > Thanks, > > Charlie -- http://mail.python.org/mailman/listinfo/python-list
