On Jan 21, 2:07 am, Marco Mariani <ma...@sferacarta.com> wrote:
> Carsten Haese wrote:
> > In order to not deprive you of the sense of accomplishment
>
> Sorry for spoiling that. If you still want the sense of accomplishment,
> try to reimplement dateutil (and rrule). It's not as easy as it seems :-o
True, but getting the last day of a given month from first principles
without any library routines is nowhere near as complex as (e.g.)
converting (y,m,d) <-> ordinal day number.
It's this easy:
# days in month (non-leap year)
_dim = (None, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31)
def _leap(y):
if y % 4: return 0
if y % 100: return 1
if y % 400: return 0
return 1
def last_day_of_month(y, m):
"""Return day (1..31) which is last day of month m in year y
"""
if m == 2:
return 28 + _leap(y)
if not (1 <= m <= 12):
raise Exception("month not in 1..12")
return _dim[m]
Cheers,
John
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