Ken Pu wrote:
Hi, below is the code I thought should create two generates, it[0] =
0,1,2,3,4,5, and it[1] = 0,10,20,30,..., but they turn out to be the
same!!!
from itertools import *
itlist = [0,0]
for i in range(2):
itlist[i] = (x+(i*10) for x in count())
...
print list(islice(itlist[0], 5))
print list(islice(itlist[1], 5))
... -- lazy evaluation doesn't evaluate
(x+(i*10) for x in count()) until the end.
Nope, that generator expression is evaluated in your assignment.
The expression x+(i*10) is evaluated at each step of the generator.
> But is this the right behaviour?
It is the defined behavior.
For what you want:
import itertools as it
def count_from(base):
for n in it.count():
yield n + base
itlist = [count_from(n) for n in range(2)]
--Scott David Daniels
scott.dani...@acm.org
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