In my application embedding Python I want to have the standard Python
module path, so I try to achieve this by setting the program path to
that of the the interpreter. Even though I call Py_SetProgramName
before Py_InitializeEx, however, Python thinks the program path (as
returned by Py_GetProgramFullPath) is that of my embedding executable.
I would love if someone could explain what is going wrong here, and
eventually provide a better solution for inheriting the Python
interpreter's standard module path.
Test application demonstrating the problem.
#include <Python.h>
int main() {
// Hardcoded for simplicity
Py_SetProgramName("C:\\Python26\\python.exe");
Py_InitializeEx(0);
printf("Program path: %s\n", Py_GetProgramFullPath());
Py_Finalize();
return 0;
}
Thanks,
Arve Knudsen
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