On Tue, 2009-01-13 at 16:13 +0100, TP wrote: > Hi everybody, > > Try the following program: > > #################### > def f(): > def f_nested(): > exec "a=2" > print a > f() > #################### > > It yields an error. > $ python nested_exec.py > File "nested_exec.py", line 3 > exec "a=2" > SyntaxError: unqualified exec is not allowed in function 'f_nested' it is a > nested function > > What is the problem? > Why? >
I believe because in the above example what namespace is local for the exec is ambiguous so you need to specify it explicitly. Also, and I'm sure you know this, exec can be dangerous and should be used wisely/rarely. -- http://mail.python.org/mailman/listinfo/python-list
