On Tue, Jan 6, 2009 at 6:56 PM, Steven Woody <narkewo...@gmail.com> wrote:
> Hi,
>
> I am trying define an Exception as below:
>
> class MyError(Exception):
> def __init__(self, message):
> self.message = message
>
> And, I expect that when I raise a MyError as
> raise MyError, "my message"
> the python should print a line such as
> MyError: my message
>
> But I did not get that, I just got:
> ...
> MyError
>
> I guess I had made something wrong with the __init__() definition, but
> I can not find an answer in doc. Please help, thanks!
You need to call the superclass constructor:
#note: this code will be different in Py 3.0
class MyError(Exception):
def __init__(self, message):
super(MyError, self).__init__(message)
Or if you're not going to add anything else to MyError, you might as
well just leave the class body empty and it'll use Exception's
__init__, which takes care of the message.
Cheers,
Chris
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