On Tue, Dec 30, 2008 at 11:43 AM, James Mills
<prolo...@shortcircuit.net.au> wrote:
> On Tue, Dec 30, 2008 at 11:38 AM, Ross <ross.j...@gmail.com> wrote:
>> I realize the code isn't counting, but how am I to do this without
>> using an if statement as the problem instructs?
>
> I just gave you a hint :)
Ross:
This exercise is a simple exercise dealing with:
* assignments
* functions
* dictionaries
* looping
* attributes and methods
>>> def histogram(s):
... d = dict()
... for c in s:
... d[c] = d.get(c, 0) + 1
... return d
...
>>> histogram("Hello World!")
{'!': 1, ' ': 1, 'e': 1, 'd': 1, 'H': 1, 'l': 3, 'o': 2, 'r': 1, 'W': 1}
Note the 3rd line of the function ?
1. Get the value (with a default of 0) of the key c from the dictionary d
2. Add 1 to this value
3. Store in d with key c
Hope this helps.
cheers
James
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