Maurice LING wrote: > Hi, > > I'm looking for a way to do this: I need to scan a text (paragraph or
> so) and look for occurrences of "<text-x> (<text-x>)". That is, if the > text just before the open bracket is the same as the text in the > brackets, then I have to delete the brackets, with the text in it. > > Does anyone knows any way to achieve this? > > The closest I've seen is > (http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/305306) by > Raymond Hettinger > > >>> s = 'People of [planet], take us to your leader.' > >>> d = dict(planet='Earth') > >>> print convert_template(s) % d > People of Earth, take us to your leader. > > >>> s = 'People of <planet>, take us to your leader.' > >>> print convert_template(s, '<', '>') % d > People of Earth, take us to your leader. > > """ > > import re > > def convert_template(template, opener='[', closer=']'): > opener = re.escape(opener) > closer = re.escape(closer) > pattern = re.compile(opener + '([_A-Za-z][_A-Za-z0-9]*)' + closer) > return re.sub(pattern, r'%(\1)s', template.replace('%','%%')) > > Cheers > Maurice Try this: import re my_expr = re.compile(r'(\w+) (\(\1\))') s = "this is (is) a test" print my_expr.sub(r'\1', s) #prints 'this is a test' M@ -- http://mail.python.org/mailman/listinfo/python-list
