In article <6d3291c3-4e12-4bdd-884a-21f15f38d...@a12g2000pro.googlegroups.com>, goat...@gmail.com wrote:
> In my python code I use subprocess.Popen to run and external program > who will listen to a TCP port. And I also create a socket to connect > to the TCP port that the external program is listening. > I will get 'Connection refused, errno=111' when I try to > socket.connect(). > Class a: > def run() > subprocess.Popen(..) > Class b: > def run(): > sock = socket.socket() > sock.connect(..) > ################################# > test.py > # socket connect will fail here > a.run() > b.run() > ################################### > test1.py > if __name__ = '__main__': > a.run() > > test2.py > # socket will connect fine > if __name__ = '__main__': > b.run Sounds like a timing problem. I assume that the process started by a.run() creates a socket and does a bind/listen/accept sequence on it. The problem is, there's nothing in your code which guarantees that this happens before b.run() executes the connect() call. The cheesy way to test this is to sleep for a second somewhere between a.run() and b.run(). See if that helps. If it doesn't, then it's possible the process started by a.run() isn't doing what it's supposed to do. Try running test1.py, and while it's running, run netstat to see if you've got something listening on the port you expect. -- http://mail.python.org/mailman/listinfo/python-list
